(3x+4)2+(4x-1)2 + (2x+5)(2x-5)
=9x2+24x+16+16x2-8x+1+4x2-25
=29x2+16x-8
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\(\left(3x+4\right)^2+\left(4x-1\right)^2+\left(2x+5\right)\left(2x-5\right)\)
\(=9x^2+24x+16+16x^2-8x+1+4x^2+25\)
\(=9x^2+16x^2+4x^2+24x-8x+16+1+25\)
\(=29x^2+16x+4x\)
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