a/ ĐKXĐ : \(x\ge0;x\ne9;x\ne4\)
Ta có :
\(P=\left(\frac{2\sqrt{x}}{9-x}+\frac{1}{3+\sqrt{x}}\right).\frac{x\left(3-\sqrt{x}\right)}{\sqrt{x}-2}\)
\(=\left(\frac{2\sqrt{x}}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}+\frac{3-\sqrt{x}}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}\right).\frac{x\left(3-\sqrt{x}\right)}{\sqrt{x-2}}\)
\(=\frac{\sqrt{x}+3}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}.\frac{x\left(3-\sqrt{x}\right)}{\sqrt{x}-2}\)
\(=\frac{1}{\sqrt{x}-2}\)
Vậy \(P=\frac{1}{\sqrt{x}-2}\) với ĐKXĐ \(x\ge0;x\ne9;x\ne4\)
b/ Với ĐKXĐ \(x\ne0;x\ne9;x\ne4\) ta có :
\(P=-\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{\sqrt{x}-2}=-\frac{1}{3}\)
\(\Leftrightarrow2-\sqrt{x}=3\)
\(\Leftrightarrow\sqrt{x}=-1\) (vô lí)
Vậy không tìm đc x thỏa mãn