Question

Phân tích thành nhân tử:

\(\left(x^2+y^2-z^2\right)^2-4x^2y^2\)

Answer 1

\(\left(x^2+y^2-z^2\right)^2-4x^2y^2\)

\(=\left(x^2+y^2-z^2\right)^2-\left(2xy\right)^2\)

\(=\left(x^2+y^2-z^2-2xy\right)\left(x^2+y^2-z^2+2xy\right)\)

Answer 2

\(=\left(x^2+y^2-z^2-2xy\right)\left(x^2+y^2-z^2+2xy\right)\)

\(=\left[\left(x+y\right)^2-z^2\right]\left[\left(x-y\right)^2-z^2\right]\)

\(=\left(x+y+z\right)\left(x+y-z\right)\left(x-y-z\right)\left(x-y+z\right)\)