Question

phân tích đa thức thành nhân tử

x^5-x^4+1

x^5+x^4+1

Answer 1

\(x^5+x^4+1\\ \Leftrightarrow x^5+x^4+x^3-x^2-x+1-x^3+x+x^2\\ \Leftrightarrow\left(x^5+x^4+x^3\right)-\left(x^3+x^2+x\right)+\left(x^2+x+1\right)\\ \Leftrightarrow x^3\left(x^2+x+1\right)-x\left(x^2+x+1\right)+\left(x^2+x+1\right)\\ \Leftrightarrow\left(x^2+x+1\right)\left(x^3-x+1\right)\)

Answer 2

đúng đề ko z

Answer 3

a: Sửa đề: x^5-x^4-1

=x^5-x^4+x^3-x^3-1

=x^3(x^2-x+1)-(x+1)(x^2-x+1)

=(x^2-x+1)(x^3-x-1)

b: x^5+x^4+1

=x^5-x^2+x^4-x+x^2+x+1

=x^2(x-1)(x^2+x+1)+x(x-1)(x^2+x+1)+(x^2+x+1)

=(x^2+x+1)(x^3-x^2+x^2-x+1)

=(x^2+x+1)(x^3-x+1)