a, \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
\(n_{H2}=n_{Zn}=\frac{6,5}{65}=0,1\left(mol\right)\)
\(\Rightarrow n_{H2}=0,1.22,4=2,24\left(l\right)\)
b,\(V_{H2SO4}=\frac{114}{1,14}=100\left(ml\right)=0,1\left(l\right)\)
\(n_{H2SO4}=n_{Zn}=0,1\left(mol\right)\)
\(\Rightarrow CM_{H2SO4}=\frac{0,1}{0,1}=1M\)
c,\(H_2+CuO\underrightarrow{^{to}}Cu+H_2O\)
\(n_{H2}=0,1\left(mol\right)\)
\(n_{CuO}=\frac{16}{80}=0,2\left(mol\right)\)
Nên H2 hết, CuO dư
Chất rắn sau phản ứng gồm Cu và CuO
\(\Rightarrow m=0,1.64+0,1.80=14,4\left(g\right)\)