Question

Mọi người làm giúp mình ạ

Answer 1

a: \(A=\left(\sqrt{3}-2+\sqrt{2}\right)-\sqrt{3}+\sqrt{2}=-2+2\sqrt{2}\)

\(B=\dfrac{x+2\sqrt{x}+8+2\sqrt{x}-8}{x-16}=\dfrac{x+4\sqrt{x}}{x-16}=\dfrac{\sqrt{x}}{\sqrt{x}-4}\)

b: Để B-1/2A=0 thì B=1/2A

\(\Leftrightarrow\dfrac{\sqrt{x}}{\sqrt{x}-4}=\sqrt{2}-1\)

\(\Leftrightarrow\sqrt{x}=\sqrt{2}\sqrt{x}-\sqrt{x}-4\sqrt{2}+4\)

\(\Leftrightarrow\sqrt{x}\left(2-\sqrt{2}\right)=-4\sqrt{2}+4\)

\(\Leftrightarrow\sqrt{x}=-2\sqrt{2}\)(vô lý)