\(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)\(\left(1\right)\)
Mà \(\left\{{}\begin{matrix}\left(2x-5\right)^{2000}\ge0\\\left(3y+4\right)^{2002}\ge0\end{matrix}\right.\)
\(\Leftrightarrow\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\ge0\left(2\right)\)
Từ \(\left(1\right)+\left(2\right)\Leftrightarrow\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}=0\)
Mà \(\left\{{}\begin{matrix}\left(2x-5\right)^{2000}\ge0\\\left(3y+4\right)^{2002}\ge0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-5\right)^{2000}=0\\\left(3y+4\right)^{2002}=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-5=0\\3y+4=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{5}{2}\\y=-\dfrac{4}{3}\end{matrix}\right.\)
Vậy ..
Ta có : \(\left\{{}\begin{matrix}\left(2x-5\right)^{2000}\ge0\\\left(3y+4\right)^{2002}\ge0\end{matrix}\right.\)
Mà \(\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}\le0\)
\(\Rightarrow\left(2x-5\right)^{2000}+\left(3y+4\right)^{2002}=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-5=0\\3y+4=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}2x=5\\3y=-4\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{5}{2}\\y=-\dfrac{4}{3}\end{matrix}\right.\)
Vậy \(x=\dfrac{5}{2}\) \(;y=-\dfrac{4}{3}\)