Question

giúp mk

Answer 1

\(CM:\Delta ABC\) vuông (Bộ 3 pitago)

Xét\(\Delta ABC\&\Delta HBA\) có:

\(\left\{{}\begin{matrix}\widehat{A}=\widehat{H}\left(=90^o\right)\\Chung\widehat{B}\end{matrix}\right.\)

\(\Rightarrow\Delta ABC\) đồng dạng với \(\Delta HBA\)(g.g)

=> \(\dfrac{AB}{BC}=\dfrac{AH}{AC}\)

\(\Rightarrow\dfrac{8}{17}=\dfrac{AH}{15}\)

\(\Rightarrow AH=\dfrac{8\times15}{17}=\dfrac{120}{17}\)

Answer 2

120/17