\(xy+2x+10y+19=0\)
\(\Rightarrow x\left(y+2\right)+10y+20=1\)
\(\Rightarrow x\left(y+2\right)+10\left(y+2\right)=1\)
\(\Rightarrow\left(x+10\right)\left(y+2\right)=1\)
Ta có bảng sau:
x + 10 | 1 | -1 |
y + 2 | 1 | -1 |
x | -9 | -11 |
y | -1 | -3 |
Vậy cặp số \(\left(x;y\right)\) là \(\left(-9;-1\right);\left(-11;-3\right)\)