cÂU 9.
\(I=\dfrac{\xi}{r+R_N}=\dfrac{20}{5+10}=\dfrac{4}{3}A\)
\(P_R=I^2_R\cdot R=\dfrac{4}{3}\cdot10=\dfrac{40}{3}W\)
\(P=\xi\cdot I=20\cdot\dfrac{4}{3}=\dfrac{80}{3}W\)
\(H=\dfrac{R}{r+R}=\dfrac{10}{5+10}=\dfrac{2}{3}\approx66,67\%\)
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