\(n_{Zn}=\dfrac{36}{65}=0,4\left(mol\right)\)
Pt : \(2Zn+O_2\rightarrow\left(t_o\right)2ZnO|\)
2 1 2
0,4 0,2 0,4
a) \(n_{H2}=\dfrac{0,4.1}{2}=0,2\left(mol\right)\)
\(V_{H2\left(dktc\right)}=0,2.22,4=4,48\left(l\right)\)
b) \(n_{ZnO}=\dfrac{0,2.2}{1}=0,4\left(mol\right)\)
⇒ \(m_{ZnO}=0,4.81=32,4\left(g\right)\)
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PTHH:\(Zn+\dfrac{1}{2}O_2\xrightarrow[]{t^o}ZnO\)
Ta có: \(n_{Zn}=\dfrac{26}{65}=0,4\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}n_{O_2}=0,2\left(mol\right)\\n_{ZnO}=0,4\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}V_{O_2}=0,2\cdot22,4=4,48\left(l\right)\\m_{ZnO}=0,4\cdot81=32,4\left(g\right)\end{matrix}\right.\)