Question

Giải pt

\(2sin^22x+sin7x-1=sinx\)

Answer 1

\(\Leftrightarrow1-cos4x+sin7x-1=sinx\)

\(\Leftrightarrow sin7x-sinx-cos4x=0\)

\(\Leftrightarrow2.cos4x.sin3x-cos4x=0\)

\(\Leftrightarrow cos4x\left(2.sin3x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}cos4x=0\\sin3x=\dfrac{1}{2}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}4x=\dfrac{\pi}{2}+k\pi\\3x=\dfrac{\pi}{6}+k2\pi\\3x=\pi-\dfrac{\pi}{6}+k2\pi\end{matrix}\right.\)(\(k\in Z\)) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{8}+\dfrac{k\pi}{4}\\x=\dfrac{\pi}{18}+\dfrac{k2\pi}{3}\\x=\dfrac{5\pi}{18}+\dfrac{k2\pi}{3}\end{matrix}\right.\) (\(k\in Z\))

Kết luận:...