Giải PT sau:
a, 3x - 7 = 0
b, 8 - 5x = 0
c, 3x - 2 = 5x + 8
d, \(\dfrac{3x-2}{3}\) = \(\dfrac{1-x}{2}\)
e, ( 5x + 1)(x - 3) = 0
f, (x + 1)(2x - 3) = 0
g, 4x(x + 3) - 5(x + 3) = 0
h, 8(x - 6) - 2x(6 - x) = 0
i, \(\dfrac{2}{x-1}\) + \(\dfrac{1}{x}\) = \(\dfrac{2x+5}{x^2-x}\)
k, \(\dfrac{3}{x+2}\) - \(\dfrac{2}{x-2}\) = \(\dfrac{2-x}{x^2-4}\)
m, \(\dfrac{3}{x}\) - \(\dfrac{2}{x-3}\) = \(\dfrac{4-x}{x^2-3}\)
n,\(\dfrac{3}{2x+10}\)+ \(\dfrac{2x}{x^2-25}\) = \(\dfrac{3}{x-5}\)
u, \(\dfrac{2}{x+3}\) - \(\dfrac{3}{x-2}\) = \(\dfrac{x+4}{\left(x+3\right)\left(x-2\right)}\)
giải pt:
a) x^5 + 2x^4 + 3x^3 + 3x^2 + 2x +1=0
b) x^4 + 3x^3 - 2x^2 + x - 3 = 0
1. C/m pt sau vô nghiệm
x^4 - 2x^3 + 3x^2 - 2x + 1 =0
2.giải pt
(x^2-4)^2=8x + 1
Giải PT:
\(\left(2x^2-3x-1\right)^2-3\left(2x^2-3x-5\right)-16=0\)
3.Giải pt : 2x2 + 3x2 + 3x +1 = 0
giải pt:
(2x-3)2+(x+1)2=3x(x-2)
Bài 1: giải pt
a, \(\frac{4}{x-2}\)+ \(\frac{1}{x+3}\)=0
Bài2 giải bất pt và biểu diễn trên truc số
a, 3x(2x+1)+4<2x(3x-1)-6 b, (2x-3)\(^2\)<(2x+5)(2x-5)
giúp mk nha
giai bpt:
a) \(\frac{x-2}{4}+\frac{3x+4}{3}< 0\)
b) \(\frac{6x+9}{x-4}>0\)
c) \(\frac{2x-3}{2x+3}+\frac{2x+3}{2x-3}< 0\)
d) \(\frac{2x-3}{35}+\frac{x\left(x-2\right)}{7}\le\frac{x^2}{7}-\frac{2x-3}{5}\)
1,Giải Pt
a,\(\frac{3x-7}{2}+\frac{x+1}{3}=-16\)
b,\(x-\frac{x+1}{3}=\frac{2x+1}{5}\)
c,\(\frac{7-3x}{12}+\frac{3}{4}=2\left(x-2\right)+\frac{5\left(5-2x\right)}{6}\)
e,\(\frac{3\left(x+3\right)}{4}+\frac{1}{2}=\frac{5x+9}{3}-\frac{7x-9}{4}\)
