ĐKXĐ: \(x\ge\frac{3}{2}\)
\(\Leftrightarrow x^2-2x-2\sqrt{2x-3}+2=0\)
\(\Leftrightarrow x^2-4x+4+2\left(x-1-\sqrt{2x-3}\right)=0\)
\(\Leftrightarrow x^2-4x+4+\frac{2\left(x^2-4x+4\right)}{x-1+\sqrt{2x-3}}=0\)
\(\Leftrightarrow\left(x-2\right)^2\left(1+\frac{2}{x-1+\sqrt{2x-3}}\right)=0\)
\(\Leftrightarrow x=2\)