(x+1)3(x+1-2)-3=0
\(\Leftrightarrow\) (x+1)3(x+1)-3=0
\(\Leftrightarrow\) (x+1)2(x2-1)-3=0
\(\Leftrightarrow\)(x2+2x+1)(x2-1)-3=0
\(\Leftrightarrow\)x4-2x3-2x-4=0
\(\Leftrightarrow\)x3(x-2)-2(x-2)=0
\(\Leftrightarrow\)(x-2)(x3-2)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x^3-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\sqrt[3]{2}\end{matrix}\right.\)
Đúng 0
Bình luận (2)
