Giải hệ phương trình:
1, \(\left\{{}\begin{matrix}x^2+1+y^2+xy=y\\x+y-2=\frac{y}{1+x^2}\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^3+8y^3-4xy^2=1\\2x^4+8y^4-2x-y=0\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}x^2+y^2=\frac{1}{5}\\4x^2+3x-\frac{57}{25}=-y\left(3x+1\right)\end{matrix}\right.\)
4, \(\left\{{}\begin{matrix}\sqrt{12-y}+\sqrt{y\left(12-x\right)}=12\\x^3-8x-1=2\sqrt{y-2}\end{matrix}\right.\)
5, \(\left\{{}\begin{matrix}\left(1-y\right)\sqrt{x-y}+x=2+\left(x-y-1\right)\sqrt{y}\\2y^2-3x+6y+1=2\sqrt{x-2y}-\sqrt{4x-5y-3}\end{matrix}\right.\)
Hpt tương đương với hpt\(\left\{{}\begin{matrix}2x-5y=5\\2x+3y=5\end{matrix}\right.\)là:
A,\(\left\{{}\begin{matrix}2x-5y=5\\4x+8y=10\end{matrix}\right.\) B,\(\left\{{}\begin{matrix}2x-5y=5\\0x-2y=0\end{matrix}\right.\) C,\(\left\{{}\begin{matrix}2x-5y=5\\2x-8y=10\end{matrix}\right.\) D,\(\left\{{}\begin{matrix}\frac{2}{5}x-y=1\\\frac{2}{3}x+y=\frac{5}{3}\end{matrix}\right.\)
Giải thích hộ mk nha
Giải hệ:
a,\(\left\{{}\begin{matrix}3\left(x-y\right)-y=11\\x-2\left(x+5y\right)=-15\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}\frac{x+y}{3}-\frac{2}{3}=2\\\frac{4x-y}{6}+\frac{x}{4}=1\end{matrix}\right.\)
Giải hệ pt:
a)\(\left\{{}\begin{matrix}x^2+y^2+x+y=18\\x\left(x+1\right).y\left(y+1\right)=72\end{matrix}\right.\) b) \(\left\{{}\begin{matrix}\frac{1}{x}+\frac{1}{y+1}=1\\3y-1=xy\end{matrix}\right.\) c)\(\left\{{}\begin{matrix}2x+3y=xy+5\\\frac{1}{x}+\frac{1}{y+1}=1\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\sqrt{\frac{x}{y}}-3\sqrt{\frac{y}{x}}=2\\x-y+xy=1\end{matrix}\right.\) e)\(\left\{{}\begin{matrix}xy+x+y=x^2-2y^2\\x\sqrt{2y}-y\sqrt{x-1}=2x-2y\end{matrix}\right.\)
HELP ME :((
Giải các hệ phương trình sau
a)\(\left\{{}\begin{matrix}\frac{1}{x}+\frac{1}{y+1}=1\\2x+3y=xy+5\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\left(x-y\right)^2+3\left(x-y\right)=4\\2x+3y=12\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\frac{x}{y}+\frac{y}{x}=\frac{13}{6}\\x+y=5\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}x+y+xy=7\\x+y^2+xy=13\end{matrix}\right.\)
Giải hệ phương trình \(\left\{{}\begin{matrix}\frac{x^2}{y^2+2y+1}+\frac{y^2}{x^2+2x+1}=\frac{1}{2}\\4xy=\left(x+1\right)\left(y+1\right)\end{matrix}\right.\)
Giải hệ phương trình:
a, \(\left\{{}\begin{matrix}\frac{x}{2}=\frac{y}{3}\\\frac{x+8}{y+4}=\frac{9}{4}\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}0,75x-3,2y=10\\x\sqrt{3}-y\sqrt{2}=4\sqrt{3}\end{matrix}\right.\)
c,\(\left\{{}\begin{matrix}\frac{2x+3}{y-1}=\frac{4x+1}{2y+1}\\\frac{x+2}{y-1}=\frac{x-4}{y+2}\end{matrix}\right.\)
Giúp tớ với,tớ sắp phải nộp bài cho cô rồi
1/\(\left\{{}\begin{matrix}\frac{5}{x+3}-\frac{9}{y-2}=100\\\frac{3}{x+3}+\frac{7}{y-2}=308\end{matrix}\right.\)
2/\(\left\{{}\begin{matrix}\frac{3x}{x+1}-\frac{2y}{y+4}=4\\\frac{2x}{x+1}-\frac{5y}{y+4}=9\end{matrix}\right.\)
MỌI NGƯỜI GIÚP MÌNH VỚI !!!
Giải các hệ PT sau:
a) \(\left\{{}\begin{matrix}2x^2-3xy=y^2-3x-1\\2y^2-3xy=x^2-3y-1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}x^3-2y=4\\y^3-2x=4\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}\sqrt{x+1}-\sqrt{7-y}=4\\\sqrt{y+1}-\sqrt{7-x}=4\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}2x^2=y+\frac{1}{y}\\2y^2=x+\frac{1}{x}\end{matrix}\right.\)
