Question

giải giúp em vs ạ.

Answer 1

Ta có: \(sin^2\alpha+cos^2\alpha=1\)

\(\Rightarrow sin\alpha=\sqrt{1-cos^2\alpha}=\sqrt{1-\left(\dfrac{\sqrt{3}}{2}\right)^2}=\dfrac{1}{2}\)

Ta có:  \(tan\alpha=\dfrac{sin\alpha}{cos\alpha}=\dfrac{1}{2}:\dfrac{\sqrt{3}}{2}=\dfrac{1}{\sqrt{3}}=\dfrac{\sqrt{3}}{3}\)

Ta có: \(tan\alpha.cot\alpha=1\)

\(\Rightarrow cot\alpha=\dfrac{1}{tan\alpha}=1:\dfrac{\sqrt{3}}{3}=\dfrac{3}{\sqrt{3}}=\sqrt{3}\)