2.
ĐKXĐ: \(\left\{{}\begin{matrix}x+3-4m>0\\2m+3-x\ge0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x>4m-3\\x\le2m+3\end{matrix}\right.\)
\(\Rightarrow x\in D=(4m-3;2m+3]\) với \(m< 3\)
a. Để hàm số xác định trên khoảng đã cho
\(\Leftrightarrow\left(-1;2\right)\subset D\Leftrightarrow\left\{{}\begin{matrix}-1\ge4m-3\\2\le2m+3\end{matrix}\right.\)
\(\Leftrightarrow-\dfrac{1}{2}\le m\le\dfrac{1}{2}\)
b.
\(\left[-1;2\right]\subset D\Leftrightarrow\left\{{}\begin{matrix}-1>4m-3\\2\le2m+3\end{matrix}\right.\)
\(\Leftrightarrow-\dfrac{1}{2}\le m< \dfrac{1}{2}\)