Question

giải các phương trình sau

x+2/50+x+4/49=x+6/48+x+8/47

Answer 1

PT <=> \(\left(\frac{x+2}{50}+2\right)+\left(\frac{x+4}{49}+2\right)=\left(\frac{x+6}{48}+2\right)+\left(\frac{x+8}{47}+2\right)\)

<=> \(\frac{x+102}{50}+\frac{x+102}{49}=\frac{x+102}{48}+\frac{x+102}{47}\)

<=> \(\left(x+102\right)\left(\frac{1}{50}+\frac{1}{49}-\frac{1}{48}-\frac{1}{47}\right)=0\)

Mà \(\frac{1}{50}+\frac{1}{49}-\frac{1}{48}-\frac{1}{47}\ne0\)

<=> x + 102 = 0

<=> x = -102