Question

giá trị x dương thỏa mãn x^4=(1/4)^2

vậy x là

Answer 1

Ta có:

\(x^4=\left(\dfrac{1}{4}\right)^2\\ hay:x^4=\left(\left(\dfrac{1}{2}\right)^2\right)^2\\ \Rightarrow x^4=\left(\dfrac{1}{2}\right)^4\\ \Rightarrow x^4=\left(\pm\dfrac{1}{2}\right)^4\\ \Rightarrow x=\pm\dfrac{1}{2}\)

Vì x dương nên: \(x=\dfrac{1}{2}\)

Answer 2

Ta có bài toán:

\(x^4=\left(\dfrac{1}{4}\right)^2\)

\(x^4=\dfrac{1}{16}\)

\(x=\sqrt[4]{\dfrac{1}{16}}\)

\(x=\dfrac{1}{2}\)

Answer 3

1/2

Answer 4

1/2

Answer 5

Ta co \(x^4=\left(\dfrac{1}{4}\right)^2\)

\(=>x^4=\dfrac{1}{16}\)

\(=>x^4=\left(\dfrac{1}{2}\right)^4\)

\(=>x=\dfrac{1}{2}\) hoặc \(\dfrac{-1}{2}\)

Vậy x ={\(\dfrac{-1}{2};\dfrac{1}{2}\)}

tick cho mk nha

Answer 6

ko có gt x dương nào thỏa mãn