Question

giá trị của B = lim (4n^2 + 3n+1)/(3n-1)^2 =

Answer 1

\(B=\lim\limits\dfrac{4n^2+3n+1}{\left(3n-1\right)^2}=\lim\limits\dfrac{\dfrac{4n^2}{n^2}+\dfrac{3n}{n^2}+\dfrac{1}{n^2}}{\dfrac{9n^2}{n^2}-\dfrac{6n}{n^2}+1}=\dfrac{4}{9}\)