Question

\(\frac{2x-1}{3}+\frac{3x-2}{4}=\frac{4x-3}{5}\)

Answer 1

\(\frac{2x-1}{3}+\frac{3x-2}{4}=\frac{4x-3}{5}\)

\(\Leftrightarrow20\left(x-1\right)+15\left(3x-2\right)=12\left(4x-3\right)\)

\(\Leftrightarrow20x-20+45x-30=60x-36\)

\(\Leftrightarrow5x-14=0\Leftrightarrow x=\frac{14}{5}\)

Answer 2

\(\frac{2x-1}{3}+\frac{3x-2}{4}=\frac{4x-3}{5}\\ \Leftrightarrow\frac{40x-20}{60}+\frac{45x-30}{60}=\frac{48x-36}{60}\\ \Leftrightarrow40x-20+45x-30=48x-36\\ \Leftrightarrow40x+45x-48x=20+30-36\\ \Leftrightarrow47x=47\\ \Leftrightarrow x=1\)

Vậy \(S=\left\{1\right\}\)