Question

(\(\frac{1}{2}\))^2x-1=\(\frac{1}{8}\)

Answer 1

Answer 2

\(\left(\frac{1}{2}\right)^{2x-1}\) như thế này hả

Answer 3

\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)

\(\left(\frac{1}{2}\right)^{2x-1}= \left(\frac{1}{2}\right)^3\)

\(\Rightarrow2x-1=3\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

Answer 4

Ta có: \(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)

\(\Rightarrow\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)

=> 2x - 1 = 3

=> 2x = 3 + 1

=> 2x = 4

=> x = 4 : 2 

=> x = 2

Vậy x = 2

Chúc bn hok tốt!