Question

Đốt cháy hoàn toàn 1,605 gam hợp chất hữu cơ A thu được 4,62 gam CO2; 1,215 gam H2O và 168ml N2(đktc)

Answer 1

\(n_{CO_2}=\dfrac{4.62}{44}=0.105\left(mol\right)\Rightarrow n_C=0.105\left(mol\right)\Rightarrow m_C=1.26\left(g\right)\)

\(n_{H_2O}=\dfrac{1.215}{18}=0.0675\left(mol\right)\Rightarrow n_H=0.135\left(mol\right)\)

\(n_{N_2}=\dfrac{0.168}{22.4}=0.0075\left(mol\right)\Rightarrow n_N=0.015\left(mol\right)\Rightarrow m_N=0.015\cdot14=0.21\left(g\right)\)

\(m_O=1.605-1.26-0.135-0.21=0\)

\(Gọi:CTHH:C_xH_yN_z\)

\(x:y:z=0.105:0.135:0.015=7:9:1\)

\(CT:C_7H_9N\)