\(\dfrac{8^5.16^3}{4^{13}}-\dfrac{3^{33}.4^5}{6^{33}}=\dfrac{\left(2^3\right)^5.\left(2^4\right)^3}{\left(2^2\right)^{13}}-\dfrac{3^{33}.\left(2^2\right)^3}{\left(2.3\right)^{33}}\)
\(=\dfrac{2^{15}.2^{12}}{2^{26}}-\dfrac{3^{33}.2^6}{2^{33}.3^{33}}\)
\(=2-\dfrac{1}{2^{27}}\)