Cộng hai vế với 1
\(\Rightarrow\dfrac{x+1}{9}+\dfrac{x+4}{6}+\dfrac{x+5}{5}+3=\dfrac{x+2}{8}+\dfrac{x+3}{7}+\dfrac{x+6}{4}+3\)
\(\Rightarrow\left(\dfrac{x+1}{9}+1\right)+\left(\dfrac{x+4}{6}+1\right)+\left(\dfrac{x+5}{5}+1\right)=\left(\dfrac{x+2}{8}+1\right)+\left(\dfrac{x+3}{7}+1\right)+\left(\dfrac{x+6}{4}+1\right)\)\(\Rightarrow\left(\dfrac{x+1}{9}+\dfrac{9}{9}\right)+\left(\dfrac{x+4}{6}+\dfrac{6}{6}\right)+\left(\dfrac{x+5}{5}+\dfrac{5}{5}\right)=\left(\dfrac{x+2}{8}+\dfrac{8}{8}\right)+\left(\dfrac{x+3}{7}+\dfrac{7}{7}\right)+\left(\dfrac{x+6}{4}+\dfrac{4}{4}\right)\)\(\Rightarrow\dfrac{x+10}{9}+\dfrac{x+10}{6}+\dfrac{x+10}{5}=\dfrac{x+10}{8}+\dfrac{x+10}{7}+\dfrac{x+10}{4}\)
\(\Rightarrow\dfrac{x+10}{9}+\dfrac{x+10}{6}+\dfrac{x+10}{5}-\dfrac{x+10}{8}-\dfrac{x+10}{7}-\dfrac{x+10}{4}=0\)
\(\Rightarrow\left(x+10\right)\left(\dfrac{1}{9}+\dfrac{1}{6}+\dfrac{1}{5}-\dfrac{1}{8}-\dfrac{1}{7}-\dfrac{1}{4}\right)=0\)
Làm nốt đi, tính như bình thường