⇒\(3\left(x+2\right)=\left(-4\right)\left(x-5\right)\)
\(3x+6=\left(-4x\right)+20\)
\(3x+4x=20-6\)
\(7x=14\)
\(\Rightarrow x=14:7\)
\(\Rightarrow x=2\)
Tìm \(x\)
1. \(\dfrac{1}{7}=\dfrac{8}{-x}\)
2. \(\dfrac{3x}{9}=\dfrac{2}{6}\)
3. \(4\dfrac{2}{5}:\left(\dfrac{-33}{10}\right)+x=-1\dfrac{5}{6}\)
4. \(45\%.x-2\dfrac{3}{8}=-1\dfrac{31}{40}\)
5. \(\left(x-2\dfrac{1}{4}\right):\left(-\dfrac{5}{6}\right)=3\)
2. tìm x
a. \(\dfrac{6}{5}\)- x =\(\dfrac{-3}{4}\)
b. \(\dfrac{3}{4}\)x - \(\dfrac{2}{3}\)x = \(\dfrac{-7}{12}\)
c. | \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\)| -1 = \(\dfrac{5}{6}\)
d. 3,2 x - (\(\dfrac{4}{5}\)+\(\dfrac{2}{3}\)) : \(3\dfrac{2}{3}\)=\(\dfrac{7}{20}\)
1. Tìm x, biết:
a, \(1\dfrac{3}{5}\) + \(\dfrac{\dfrac{2}{7}+\dfrac{2}{17}+\dfrac{2}{37}}{\dfrac{5}{7}+\dfrac{5}{17}+\dfrac{5}{37}}\) . x = \(\dfrac{16}{5}\)
b, (\(\dfrac{1}{24.25}\) + \(\dfrac{1}{25.26}\) + . . . + \(\dfrac{1}{39.40}\) ) . 120 + x. \(\dfrac{1}{3}\) = -4
c, \(\left|x-\dfrac{1}{3}\right|\) . 2 + \(\dfrac{4}{5}\) = 0,24
d, \(\dfrac{24}{7x-3}\) = \(\dfrac{-4}{25}\)
e, ( 50% x + \(5\dfrac{1}{4}\) ) , \(\dfrac{-2}{3}\) = \(2\dfrac{5}{6}\)
f, \(1\dfrac{1}{3}\) - 25%\(\dfrac{-5}{12}\) + 2x = 1,6 : \(\dfrac{3}{5}\)
Tìm x: \(\dfrac{x+2}{2010}+\dfrac{x+3}{2009}+\dfrac{x+4}{2008}+\dfrac{x+5}{2007}+\dfrac{x+2007}{5}=-5\)
Giúp mk đi mà
\(x-\dfrac{1}{5}=\dfrac{3}{4}\)
\(\dfrac{2}{5}x+\dfrac{1}{4}=\dfrac{1}{8}\)
1: \(\dfrac{2\cdot\left(x+2\right)}{3}-\dfrac{5\cdot\left(x-1\right)}{4}=\dfrac{3\cdot\left(5-x\right)}{2}-1\dfrac{1}{2}\cdot\left(2x+3\right)\)
1. tìm x
a. x+\(\dfrac{3}{4}\)=\(\dfrac{1}{2}\)
b. \(\dfrac{5}{3}\). x=\(\dfrac{4}{7}\)
c. \(\dfrac{2}{3}\): x=\(\dfrac{-1}{4}\)
d. \(\dfrac{5}{9}\)- x=\(\dfrac{4}{3}\)
e.x +\(\dfrac{4}{17}\)=\(\dfrac{2}{34}\)
f. \(3\dfrac{4}{7}\): x=11
2. tìm x
a. \(\dfrac{x}{8}\)=\(\dfrac{-9}{6}\)
b. \(\dfrac{4}{9}\)+\(\dfrac{7}{3}\):x=\(\dfrac{1}{5}\)
c. \(\dfrac{-5}{9}\)- x=\(\dfrac{4}{3}\)
d. x +\(\dfrac{4}{17}\)=\(\dfrac{2}{34}\)
e. \(\dfrac{3}{4}\).x=\(\dfrac{7}{8}\)
f. \(5\dfrac{4}{7}\): x=11
tìm x,y thuộc z
a. \(\dfrac{-1}{4}:\dfrac{-3}{4}+\dfrac{1}{2}< x< \dfrac{7}{8}-\dfrac{1}{2}:\dfrac{-5}{6}\)
\(\dfrac{-4}{8}\) - ( \(\dfrac{-1}{3}\) - x ) = \(\dfrac{2}{5}\)