Question

\(x-\dfrac{1}{5}=\dfrac{3}{4}\)

\(\dfrac{2}{5}x+\dfrac{1}{4}=\dfrac{1}{8}\)

Answer 1

a) \(x-\dfrac{1}{5}=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}+\dfrac{1}{5}\)

\(x=\dfrac{15}{20}+\dfrac{4}{20}\)

\(x=\dfrac{19}{20}\)

b) \(\dfrac{2}{5}x+\dfrac{1}{4}=\dfrac{1}{8}\)

\(\dfrac{2}{5}x=\dfrac{1}{8}-\dfrac{1}{4}\)

\(\dfrac{2}{5}x=\dfrac{1}{8}-\dfrac{2}{8}\)

\(\dfrac{2}{5}x=\dfrac{-1}{8}\)

\(x=\dfrac{-1}{8}:\dfrac{2}{5}\)

\(x=\dfrac{-1}{8}.\dfrac{5}{2}\)

\(x=\dfrac{-5}{16}\)