Question

2. tìm x

a. \(\dfrac{x}{8}\)=\(\dfrac{-9}{6}\)

b. \(\dfrac{4}{9}\)+\(\dfrac{7}{3}\):x=\(\dfrac{1}{5}\)

c. \(\dfrac{-5}{9}\)- x=\(\dfrac{4}{3}\)

d. x +\(\dfrac{4}{17}\)=\(\dfrac{2}{34}\)

e. \(\dfrac{3}{4}\).x=\(\dfrac{7}{8}\)

f. \(5\dfrac{4}{7}\): x=11

Answer 1

a)\(x.6=-72\)

=> x = -12

b)\(\dfrac{7}{3}:x=\dfrac{-11}{45}\)

=> \(x=\dfrac{-105}{11}\)

c) \(x=\dfrac{-17}{9}\)

d)\(x=\dfrac{-3}{17}\)

e) \(x=\dfrac{7}{6}\)

f) \(\dfrac{39}{7}:x=11\)

=> \(x=\dfrac{39}{77}\)

Answer 2

a)

\(\dfrac{x}{8}=\dfrac{-9}{6}\)

=> x = \(\dfrac{8.\left(-9\right)}{6}\)

=> x = -12

Answer 3

b) \(\dfrac{4}{9}+\dfrac{7}{3}:x=\dfrac{1}{5}\)

=> \(\dfrac{7}{3}:x=\dfrac{-11}{45}\)

=> x = \(\dfrac{7}{3}:-\dfrac{11}{45}=-\dfrac{105}{11}\)

Answer 4

c) \(-\dfrac{5}{9}-x=\dfrac{4}{3}\)

=> x = \(-\dfrac{17}{9}\)

d) x + \(\dfrac{4}{17}=\dfrac{2}{34}\)

=> x = \(\dfrac{2}{34}-\dfrac{4}{17}=-\dfrac{3}{17}\)

e) \(\dfrac{3}{4}.x=\dfrac{7}{8}\)

=>x = \(\dfrac{7}{6}\)