Chứng minh \(\left|a\right|+\left|b\right|\ge\left|a+b\right|\)với ab\(\ge\)0
Cho a, b, c là độ dài 3 cạnh của tam giác.
Chứng minh \(\left(a+b+c\right)\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)+\frac{3\left(a-b\right)\left(b-c\right)\left(c-a\right)}{abc}\ge9\)
cho a,b,c >0 thỏa mãn a.b.c=1. chứng minh rằng \(\dfrac{1}{a^3.\left(b+c\right)}+\dfrac{1}{b^3\left(a+c\right)}+\dfrac{1}{c^3.\left(a+b\right)}>=\dfrac{3}{2}\)
B1:C/m
a)\(\dfrac{a^2+b^2}{2}\)\(>=ab\)
b)(a+b)\(\left(\dfrac{1}{a}+\dfrac{1}{b}\right)>=4\) (với a>0,b>0)
c)\(a\left(a+2\right)< \left(a+1\right)^2\)
a, chứng minh:
\(n^4+\frac{1}{4}=\left[\left(n-1\right)n+\frac{1}{2}\right].\left[\left(n+1\right)n+\frac{1}{2}\right]\)
b, Áp dụng câu a) thu gọn:
\(\frac{\left(1^4+\frac{1}{4}\right).\left(3^4+\frac{1}{4}\right)...\left(13^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right).\left(4^4+\frac{1}{4}\right)...\left(14^4+\frac{1}{4}\right)}\)
Chứng minh các bất đẳng thức:
1. Cmr :\(a^4+3\ge4a\)
2. Cmr : \(a^2\left(1+b^2\right)+b^2\left(1+c^2\right)+c^2\left(1+a^2\right)\)
\(\dfrac{b-c}{\left(a-b\right)\left(a-c\right)}+\dfrac{c-a}{\left(b-c\right)\left(b-a\right)}+\dfrac{a-b}{\left(c-a\right)\left(c-b\right)}=\dfrac{2}{a-b}+\dfrac{2}{b-c}+\dfrac{2}{c-a}\)
Chứng minh bđt:
\(\left(a+b+c\right)\left(\dfrac{1}{a+b}+\dfrac{1}{b+c}+\dfrac{1}{a+c}\right)\ge\dfrac{9}{2}\forall a,b,c>0\)
Chứng minh các bất đẳng thức sau:
a. \(\left(a^2+b^2\right)\left(x^2+y^2\right)\ge\left(ax+by\right)^2\)
b. \(\left(a^2+b^2+c^2\right)\left(x^2+y^2+z^2\right)\ge\left(ax+by+cz\right)^2\)
