a, \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(n_{H2}=\frac{6,72}{22,4}=0,3\left(mol\right)\)
Theo phương trình : \(n_{AlCl3}=\frac{2}{3}n_{H2}=0,2\left(mol\right)\)
\(\rightarrow m_{AlCl3}=0,2.133,5=26,7\left(g\right)\)
b, Theo phương trình :
\(n_{HCl}=2n_{H2}=0,6\left(mol\right)\)
\(\rightarrow V_{HCl}=\frac{0,6}{6}=0,1\left(l\right)\)