Question

cho hai đa thức:

P(x) = 3x² - 5 + x⁴ - 3x³ - x⁶ - 2x² - x³;

Q(x) = x³ + 2x⁵ - x⁴ + x² - 2x³ + x - 1.

Tính P(x) - Q(x).

Answer 1

Answer 2

P(x)-Q(x) = (3x²-5+x⁴-3x³-x⁶-2x²-x³)-(x³+2x⁵x⁴+x²- 2x³+x-1 ) = \(3x^2-5+x^4-3x^3-x^6-2x^2-x^3-x^3-2x^5+x^4-x^2+2x^3-x+1=\left(3x^2-2x^2-x^2\right)+\left(x^4+x^4\right)+\left(-3x^3-x^3-x^3+2x^3\right)+\left(-5+1\right)-x^6-2x^5-x=2x^4-3x^3-4-x^6-2x^5-x\)=) hơi rắc rối nhé

Answer 3

P(x)-Q(x)=(3x\(^2\) - 5 + x\(^4\) - 3x\(^3\) - x\(^6\) - 2x\(^2\) - x\(^3\)) - (x\(^3\) +2x\(^5\) - x\(^4\) + x\(^2\) - 2x\(^3\) + x - 1)

=3x\(^2\) - 5 + x\(^4\) - 3x\(^3\) - x\(^6\) - 2x\(^2\) - x\(^3\) - x\(^3\) - 2x\(^5\) + x\(^4\) - x\(^2\) + 2x\(^3\) -x+1

=(3x\(^2\) - 2x\(^2\) - x\(^2\)) +(-5+1) + (x\(^4\) + x\(^4\))+(-3x\(^3\) - x\(^3\) - x\(^3\) +2x\(^3\)) + x\(^6\) - 2x\(^5\) - x

= -4 + 2x\(^4\) - 3x\(^3\) + x\(^6\) - 2x\(^5\) - x\(^{ }\)

Answer 4

chữ cuối cùng là x đó

Answer 5

sai rồi kết quả là

-4 + 2x\(^4\) - 3x\(^3\) - x\(^6\) - 2x\(^5\) - x