Question

Cho f(x) = 5x^3+3x^2-9x+1

g(x)= 4x^3-7x^3-6x-16

Tính h(x)=f(x)-g(x)

Answer 1

h(x)=f(x)-g(x)= 5x^3+3x^2-9x+1-4x³+7x³+6x+16

=8x³+3x²-3x+17

Answer 2

Ta có:     \(f\left(x\right)=5x^3+3x^2-9x+1\)

                \(g\left(x\right)=4x^3-7x^3-6x-16\)

\(h\left(x\right)=f\left(x\right)-g\left(x\right)=\left(5x^3+3x^2-9x+1\right)-\left(4x^3-7x^3-6x-16\right)\)

                                 \(=5x^3+3x^2-9x+1-4x^3+7x^3+6x+16\)

                                 \(=8x^3+3x^2-3x+17\)

Answer 3

f(x)-g(x)=h(x)

f(x)-g(x)=5x³+3x²-9x+1-(4x³-7x³-6x-16)

f(x)-g(x)=5x³+3x²-9x+1-4x³+7x³+6x+16

f(x)-g(x)=5x³-4x³+7x³+3x²+6x-9x+1+16

f(x)-g(x)=8x³+3x²-3x+17

          Vậy h(x)=8x³+3x²-3x+17

Answer 4

h(x)=8x^3+3x^2-3x+17

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