\(b^2=ac\Rightarrow\frac{b}{c}=\frac{a}{b}=\frac{2010a}{2010b}=\frac{2011b}{2011c}=\frac{2010a+2011b}{2010b+2011c}\)
\(\Rightarrow\frac{b}{c}.\frac{a}{b}=\left(\frac{2010a+2011b}{2010b+2011c}\right).\left(\frac{2010a+2011b}{2010b+2011c}\right)\)
\(\Rightarrow\frac{a}{c}=\frac{\left(2010a+2011b\right)^2}{\left(2010b+2011c\right)^2}\)
Cho; \(\dfrac{a}{2b}=\dfrac{b}{2c}=\dfrac{c}{2d}=\dfrac{d}{2a}\left(a,b,c,d>0\right)\)
Tính \(A=\dfrac{2011a-2010b}{c+d}+\dfrac{2011b-2010c}{a+d}+\dfrac{2011c-2010a}{a+b}+\dfrac{2011d-2010a}{b+c}\)
Cho\(\dfrac{a}{2b}=\dfrac{b}{2c}=\dfrac{c}{2d}=\dfrac{d}{2a}\)
tính P biết
\(\dfrac{2011a-2010b}{c+d}+\dfrac{2011b-2010c}{a+d}+\dfrac{2011c-2010d}{a+b}+\dfrac{2011d-2010a}{b+c}\)
1.a) Tìm cặp số nguyên (x; y) thỏa mãn: |y+2015|+32=\(\frac{2016}{\left(2x-6\right)^2+63}\).
b) Cho các số thực dương a, b, c thỏa mãn \(b^2\)=ac. Chứng minh rằng: \(\frac{a}{c}\)=\(\frac{\left(a+2017b\right)^2}{\left(b+2017c\right)^2}\)
Cho 3 số a,b,c thỏa mãn \(\frac{a}{2018}=\frac{b}{2019}=\frac{c}{2020}\). Chứng minh \(\left(a-c\right)^3=8\left(a-b\right)^2.\left(b-c\right)\)
Cho \(\dfrac{a}{2b}\)=\(\dfrac{b}{2c}\)=\(\dfrac{c}{2d}\)=\(\dfrac{d}{2a}\)(a,b,c,d >0). Tính A=\(\dfrac{2011a-2010b}{c+d}\)+\(\dfrac{2011b-2010c}{a+d}\)+\(\dfrac{2011c-2010d}{a+b}\)+\(\dfrac{2011d-2010a}{b+c}\)=...
Cho a, b, c khác 0 thỏa mãn a+b+c=0. Tính \(A=\left(1+\frac{a}{b}\right).\left(1+\frac{b}{c}\right).\left(1+\frac{c}{a}\right)\)
a, cho a,b,c \(\in\) R và a,b,c \(\ne\) 0 thỏa mãn \(b^2=ac\) . CMR : \(\dfrac{a}{c}=\dfrac{\left(a+2013b\right)^2}{\left(b+2013c\right)^2}\)
b, cho cá số a,b,c khác 0 thỏa mãn \(\dfrac{a+b}{c}=\dfrac{b+c}{a}=\dfrac{c+a}{b}\)
Tính M=\(\left(1+\dfrac{a}{b}\right)\left(1+\dfrac{b}{c}\right)\left(1+\dfrac{c}{a}\right)\)
Cho a,b,c thỏa mãn: \(\frac{a}{2016}=\frac{b}{2018}=\frac{c}{2020}\). Chứng minh \(\frac{\left(a-c\right)^2}{4}=\left(a-b\right).\left(b-c\right)\)
Cho a,b,c,d thỏa mãn: \(\frac{a}{2016}=\frac{b}{2018}=\frac{c}{2020}\). Chứng minh \(\frac{\left(a-c\right)^2}{4}=\left(a-b\right).\left(b-c\right)\)