a: ĐKXĐ: x<>-3; x<>2
\(M=\dfrac{x^2-4-5-x-3}{\left(x-2\right)\left(x+3\right)}=\dfrac{\left(x-4\right)\left(x+3\right)}{\left(x-2\right)\left(x+3\right)}=\dfrac{x-4}{x-2}\)
b: Để M=0 thì x-4=0
=>x=4
c: Để M nguyên thì x-2-2 chia hết cho x-2
=>\(x-2\in\left\{1;-1;2;-2\right\}\)
hay \(x\in\left\{3;1;4;0\right\}\)