Question

cho \(A=\lim\limits_{x\rightarrow+\infty}\dfrac{mx+2006}{x+\sqrt{x^2+2007}}\). tìm m để A=0

Answer 1

\(\lim\limits_{x\rightarrow+\infty}\dfrac{m+\dfrac{2006}{x}}{1+\sqrt{1+\dfrac{2007}{x^2}}}=\dfrac{m}{2}\)

\(A=0\Leftrightarrow\dfrac{m}{2}=0\Rightarrow m=0\)