14HCl + K2Cr2O7 => 2KCl + 2CrCl3 + 7H2O + 3Cl2
nHCl = \(\frac{146.36,5\%}{36,5}=1,46\left(mol\right)\)
theo phương trình , nCl2 = \(\frac{3}{14}\)nHCl = \(\frac{3.1,46}{14}\) = \(\frac{219}{700}\) (mol)
=> VCl2 = \(\frac{219}{700}.22,4=7,008\left(l\right)\)