zn +2hcl\(\rightarrow\)zncl2+h2
nzn=\(\frac{13}{65}\)=0,2mol
theo phưong trinh hoa hoc
nhcl=2*0,2=0,4 mol
\(\Rightarrow\)vhcl=0,4*22,4=8,96 lit
a) PTHH: Zn + 2HCl \(\rightarrow\) ZnCl2 + H2\(\uparrow\)
b) nZn = \(\frac{13}{65}=0,2\left(mol\right)\)