Question

CẦN GẤP

TÌM X BIẾT : 2016^(X-1).(X+2)=1

Answer 1

Giải:

Ta có:

\(2016^{\left(x-1\right)\left(x+2\right)}=1\)

\(2016^{\left(x-1\right)\left(x+2\right)}=2016^0\)

Vì \(2016=2016\)

Nên \(\left(x-1\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)

Vậy \(x=1\) hoặc \(x=-2\).

Chúc bạn học tốt!

Answer 2

: 2016^(X-1).(X+2)=1

=2016^(x-1)(x+2)=2016⁰

=> (x-1)(x+2)=0

=> \(\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)

vậy x=1 hoặc x=-2