Question

BAØI 4: Cho A = x3y B = x2y2 C = xy3
Chöùng minh rằng: A.C + B2 – 2x4y4 = 0
 

Answer 1

Ta có: \(A\cdot C+B^2-2x^4y^4=x^3y\cdot xy^3+\left(x^2y^2\right)^2-2x^4y^4\)

\(\Leftrightarrow A\cdot C+B^2-2x^4y^4=x^4y^4+x^4y^4-2xy^4\)

\(\Leftrightarrow A\cdot C+B^2-2x^4y^4=0\)(đpcm)

Answer 2

A.C + B^2 - 2x^4.y^4

=(x^3.y)(x.y^3) + x^4.y^4 - 2x^4.y^4

=(x^4.y^4 + x^4.y^4) - 2x^4.y^4

=2x^4.y^4 - 2x^4.y^4

=0