\(\lim\limits_{x\rightarrow2}f\left(x\right)=\lim\limits_{x\rightarrow2}\dfrac{x^2+x-6}{x-2}=\lim\limits_{x\rightarrow2}\dfrac{\left(x-2\right)\left(x+3\right)}{x-2}=\lim\limits_{x\rightarrow2}\left(x+3\right)=5\\ f\left(2\right)=5\\ \rightarrow\lim\limits_{x\rightarrow2}f\left(x\right)=f\left(2\right)\)
Suy ra f(x) liên tục tại x = 2.