Violympic toán 8
Các câu hỏi tương tự
MM
23 tháng 4 2019 lúc 22:38
Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
\(a,\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(b,\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)=\left(\frac{x+4}{96}+1\right)+\left(\frac{x+5}{95}+1\right)\)
Bài 5: Giải các phương trình sau :
a) frac{3x-1-frac{x-1}{2}}{3}-frac{2x+frac{1-2x}{3}}{2}frac{frac{3x-1}{2}-6}{5}
b) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27}
c) frac{x+1}{2004}+frac{x+2}{2003}frac{x+3}{2002}+frac{x+4}{2001}
d) frac{x-45}{55}+frac{x-47}{53}frac{x-55}{45}+frac{x-53}{47}
e) frac{x+2}{98}+frac{x+4}{96}frac{x+6}{94}+frac{x+8}{92}
Đọc tiếp
Bài 5: Giải các phương trình sau :
a) \(\frac{3x-1-\frac{x-1}{2}}{3}-\frac{2x+\frac{1-2x}{3}}{2}=\frac{\frac{3x-1}{2}-6}{5}\)
b) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
c) \(\frac{x+1}{2004}+\frac{x+2}{2003}=\frac{x+3}{2002}+\frac{x+4}{2001}\)
d) \(\frac{x-45}{55}+\frac{x-47}{53}=\frac{x-55}{45}+\frac{x-53}{47}\)
e) \(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\)
a) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27} b) frac{x+1}{2004}+frac{x+2}{2003}frac{x+3}{2002}+frac{x+4}{2001}
d) frac{x+1}{9}+frac{x+2}{8}frac{x+3}{7}+frac{x+4}{6}
c) frac{x-45}{55}+frac{x-47}{53}frac{x-55}{45}+frac{x-53}{47}
Đọc tiếp
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\) b) \(\frac{x+1}{2004}+\frac{x+2}{2003}=\frac{x+3}{2002}+\frac{x+4}{2001}\)
d) \(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)
c) \(\frac{x-45}{55}+\frac{x-47}{53}=\frac{x-55}{45}+\frac{x-53}{47}\)
Giaỉ PT
a) \(\left(\frac{x-1}{99}+x-99\right)+\left(\frac{x-3}{97}+\frac{x-7}{93}\right)+\left(\frac{x-5}{95}+\frac{x-95}{5}\right)=6\)
b) \(\left(4x-5\right)^2\left(2x-3\right)\left(x-1\right)=9\)
c) \(\frac{5}{x-8}+1=\frac{23}{x^2-5x-24}-\frac{2}{x+3}\)
Help !!
201-x/99 + 205-x/95 + 203-x/97 + 3 = 0
Tìm x:
\(\dfrac{x-5}{100}+\dfrac{x-4}{100}+\dfrac{x-3}{100}=\dfrac{x-100}{5}+\dfrac{x-101}{4}+\dfrac{x-102}{3}\)
\(\dfrac{29-x}{21}+\dfrac{27-x}{23}+\dfrac{25-x}{25}+\dfrac{23-x}{27}+\dfrac{21-x}{29}=-5\)
\(\dfrac{2-x}{2001}-1=\dfrac{1-x}{2002}-\dfrac{x}{2003}\)
Giải phương trình sau: \(\frac{201-x}{99}+\frac{203-x}{97}=\frac{201-x}{95}+3=0\)
201-x/99+203-x/97+205-x/96+3=0
H24
12 tháng 3 2020 lúc 14:16
a, \(\left(\frac{x+2}{98}+18\right)\left(\frac{x+3}{97}+1\right)=\left(\frac{x+4}{96}+1\right)\left(\frac{x+5}{95}+1\right)\)
b, \(\frac{x+1}{1998}+\frac{x+2}{1997}=\frac{x+3}{1996}+\frac{x+4}{1995}\)