Question

bài 1: tính

\(\frac{8^{10}+4^{10}}{6^{10}+3^{10}}\)

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Answer 1

\(\frac{8^{10}+4^{10}}{6^{10}+3^{10}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2.3\right)^{10}+3^{10}}=\frac{2^{30}+2^{20}}{2^{10}.3^{10}+3^{10}}=\frac{2^{20}\left(2^{10}+1\right)}{3^{10}\left(2^{10}+1\right)}=\frac{2^{20}}{3^{10}}\)

Answer 2

\(\dfrac{8^{10}+4^{10}}{6^{10}+3^{10}}=\dfrac{\left(8+4\right)^{10}}{\left(6+3\right)^{10}}=\left(\dfrac{12}{9}\right)^{`10}\)