Question

\(\frac{49^{24}.125^{10}.2^8-5^{30}.7_{ }^{49}.4^5}{5^{29}.16^2.7^{48}}\)

giúp mk nhanh na cảm ơn trước

Answer 1

\(\frac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)

\(=\frac{\left(7^2\right)^{24}.\left(5^3\right)^{10}.2^8-5^{30}.7^{49}.\left(2^2\right)^5}{5^{29}.\left(2^4\right)^2.7^{48}}\)

\(=\frac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{48}}\)

\(=\frac{7^{48}.5^{30}.2^8.\left(1-7.2^2\right)}{5^{29}.2^8.7^{48}}\)

\(=5.\left(1-7.4\right)\)

\(=5.\left(1-28\right)\)

\(=5.\left(-27\right)=-135\)