(1)\(2^2.x+1=32\)
4.x = 32-1
4.x=31
x=31:4
x= 7,75
(4)\(\left(x-1\right)^3-2^5=7^2\)
\(\left(x-1\right)-32=49\)
\(\left(x-1\right)=49-32\)
\(x-1=17\)
x=17+1
x=18
\(\frac{x}{3}=\frac{y}{5}=\frac{-4}{-2}=2\)=2
\(\frac{x}{3}=2=>x=3.2=6\)
\(\frac{y}{5}=2=>y=5.2=10\)
\(kl:x=6,y=10\)