Question

A/3y+1=9y²-6y+1/3y-1

Answer 1

\(a,3y+1=\dfrac{9y^2-6y+1}{3y-1}\\ \Leftrightarrow3y+1=\dfrac{\left(3y-1\right)^2}{3y-1}\\ \Leftrightarrow3y+1=3y-1\left(voli\right)??\)

Answer 2