Question

A=2 mũ 0 + 2 mũ 1 + 2 mũ 2 + ... + 2 mũ 2010

Answer 1

2A=2\(\left(2^0+2^1+2^2+...+2^{2010}\right)\)

2A=\(2^1+2^2+2^3+...+2^{2011}\)

2A-A=\(2^{2011}-2^0\)

Vậy A=\(2^{2011}-2\)

Answer 2

\(A=2^0+2 ^1+...+2^{2010}\\ \Rightarrow2.A=2+2^2+....+2^{2011}\\ \Rightarrow2.A-A=2^{2011}-1\\ \Rightarrow A=2^{2011}-1\)

Answer 3

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