Question

a, 4^x : 4  = 64

^b, 2^x  . 4 = 128 

c, x ^{17 = x}

d, x . x ^{2 .} x³ = 64 

e, 5^{x + 2} + 5  ^{x + 1} = 150

Answer 1

4^x : 4 = 64

4^(x-4) = 4³

x - 4 = 3

x     = 3 + 4

=> x = 7

Answer 2

b, \(2^x.2^2=2^7\Rightarrow2^x=2^7:2^2\)

\(\Rightarrow2^x=2^5\Rightarrow x=5\)

c, \(x^{17}=x\Rightarrow x=1\)

d, \(x.x^2.x^3=64\Rightarrow x^{1+2+3}=2^6\Rightarrow x^6=2^6\Rightarrow x=2hoacx=-2\)

Answer 3

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