\(\dfrac{9}{5}-\left(3+\dfrac{2}{5}+\dfrac{4}{5}\right)=\dfrac{9}{5}-3-\dfrac{6}{5}=\dfrac{3}{5}-3=-\dfrac{12}{5}\)
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\(\dfrac{9}{5}-\left(3+\dfrac{2}{5}+\dfrac{4}{5}\right)=\dfrac{9}{5}-3-\dfrac{6}{5}=\dfrac{3}{5}-3=-\dfrac{12}{5}\)