7/(8*x)+(5-x)/(4*x^2-8*x) = (x-1)/(2*x*(x-2))+1/(8*x-16)
5-x/4x^2+8x+7/8=x-1/2x(x-2)+1/8x-16
x^4+ 4 Bx^4 + 64 C x^8+ x^7 + 1 Dx^8 +x^4 + 1 E x^5 + x +1
F x^3 + x^2 + 4 G x^ 4 + 2x^2 - 24 H x^3 - 2x -4 I a^4 +4b^4
Giải các phương trình sau:
A) 1/x-2+3=3-x/x-2
B)8-x/x-7-8=-26/x-7
C)1/x-2+1/x-3=2/x-1
D)X^3-1/X=(x-2)(x+2)+11/x
E)x+5/x-5-x-5/x+5=20/x^2-25
F)x+7/x-3+4x-2/x-5=5
a \(x^2-x=0\) b \(x^2-2x=0\) c (x+1)(x+2)=(2-x)(x+2)
d \(\dfrac{1}{x-2}+3=\dfrac{3-x}{x-2}\) đ \(\dfrac{8-x}{x-7}-8=\dfrac{1}{x-7}\)
e \(\dfrac{x}{2\left(x-3\right)}+\dfrac{x}{2\left(x+1\right)}=\dfrac{2x}{\left(x+1\right)\left(x-3\right)}\)
f \(5+\dfrac{76}{x^2-16}=\dfrac{2x-1}{x+4}-\dfrac{3x-1}{4-x}\)
g \(\dfrac{90}{x}-\dfrac{36}{x-6}=2\) h \(\dfrac{1}{x}+\dfrac{1}{x+10}=\dfrac{1}{12}\) i \(\dfrac{x+3}{x-3}-\dfrac{1}{x}=\dfrac{3}{x\left(x-3\right)}\)
k \(\dfrac{3}{x+2}-\dfrac{2}{x-2}+\dfrac{8}{x^2-4}=0\) l \(\dfrac{3}{x+2}-\dfrac{2}{x-3}=\dfrac{8}{\left(x-3\right)\left(x+2\right)}\)
m\(\dfrac{x}{2x+6}-\dfrac{x}{2x+2}=\dfrac{3x+2}{\left(x+1\right)\left(x+3\right)}\)
n \(\dfrac{x}{x+1}-\dfrac{2x-3}{1-x}=\dfrac{3x^2+5}{x^2-1}\) j \(\dfrac{5}{x+7}+\dfrac{8}{2x+14}=\dfrac{3}{2}\)
q \(\dfrac{x-1}{x}-\dfrac{1}{x+1}=\dfrac{2x-1}{x^2+x}\)
Cần gấp ạ
tìm x biết 1+x^3+...+x^30 +x^31=(1+x)(1+x^2)(1+x^4)(1+x^8)(1+x^16)
\(\dfrac{1}{1-x}\)+\(\dfrac{1}{1+x}\)+\(\dfrac{2}{1+x^2}\)+\(\dfrac{4}{1+x^4}\)+\(\dfrac{8}{1+x^8}\)+\(\dfrac{16}{1+x^{16}}\)
1.
a) \(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
b) \(\left|12-5x\right|=4-x\)
c) \(\frac{3x+5}{2}-1\le\frac{x+2}{3}+x\)
Giúp em giải bài này với ạ Tính A=1/(x+1)(x+2) + 1/(x+2)(x+3) + 2/(x+3)(x+4) + 4/ (x+4)(x+5) + 8/ (x+5)(x+6)
